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Could you help me with this homework I have 7 minutes left

Could you help me with this homework I have 7 minutes left-example-1
User Tstr
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1 Answer

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Given:

NR = 10 m

Measure of arc MQ = 162 degrees

Let's find the length of arc NP.

Here, we have:

Measure of arc MQ = Measure of arc NP

Now apply the Angle-arc relationship, we have:

Measure of arc NP = measure of angle NRP = 162 degrees.

To find the length of arc NP, apply the formula;


arc_(NP)=(\theta)/(360)*2\pi r

Where:

θ = 162 degrees

r is the radius = NR = 10 m

Thus, we have:


\begin{gathered} arc_(NP)=(162)/(360)*2\pi *10 \\ \\ arc_(NP)=0.45*62.83 \\ \\ arc_(NP)=28.27\text{ m} \end{gathered}

Therefore, the length of arc NP is 28.27 m.

ANSWER:

28.27 m

User Katya S
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