1 Answer

Bill Sambrone · Answer 1 · 2023-06-19T18:49:52+0000

step 1

Find out the volume of the piece of steel

The volume of the figure is equal to the volume of a cylinder plus the volume of a cone

so

$V=\pi\cdot r^2\cdot h+(1)/(3)\cdot\pi^{}\cdot r^2\cdot h$

we have

h cylinder=4.5 in

r=2.28/2=1.14 in

hcone=1.5 in

substitute given values in the formula

$V=\pi\cdot1.14^2\cdot4.5+(1)/(3)\cdot\pi^{}\cdot1.14^2\cdot1.5$

V=20.4 in3

step 2

Multiply the density by the volume

0.283*20.4=5.8 lb

therefore

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