Question

find the length of a rectangle that is 6 in less than four times the width if the perimeter is 80 in find the length of the rectangle

Answer 1

`\begin{gathered} \text{The lenght is 6 less than four times the width, which means, L = 4B-6} \\ \text{where B is the Breadth/width} \\ \text{perimeter = 2(L + B) } \\ \text{perimeter = 2( }4B\text{ - 6 + B)} \\ \text{ 80 = 2(5B - 6 )} \\ 80\text{ = 10B - 12} \\ 80+12\text{ = 10B} \\ 92\text{ = 10B} \\ B\text{ = }(92)/(10)\text{ = 9.2cm} \\ L\text{ = 4B - 6} \\ L=\text{ 4 }*9.2\text{ - 6} \\ L\text{ = 36.8 - 6} \\ L\text{ = 28.8} \end{gathered}`