Question

A 91-g sample of aluminum is at an initial temperature of 22 °C. If 874 joules of heat are applied to the sample, what is the final temperature of the aluminum? c = 0.90 j/gk

Answer 1

The final temperature of the aluminum sample is 32°C.

Step-by-step explanation:

To determine the final temperature of the aluminum sample, we can use the formula Q = mcΔT, where Q is the heat applied to the sample, m is the mass of the sample, c is the specific heat capacity of aluminum, and ΔT is the change in temperature. Rearranging the formula, we have ΔT = Q / (mc).

Given that the mass of the sample is 91 g, the specific heat capacity of aluminum is 0.90 J/g°C, and 874 J of heat are applied to the sample, we can calculate the change in temperature as follows: ΔT = 874 J / (91 g * 0.90 J/g°C) = 10°C.

Therefore, the final temperature of the aluminum sample is 22°C + 10°C = 32°C.

Answer 2

Step-by-step explanation:

We have an aluminum sample that has a mass of 91 g. Its initial temperature is 22 °C and we apply to it 874 J. We have to find the final temperature of the aluminum sample.

To find the final temperature we can use the following formula:

Q = m * C * ΔT

Where Q is the amount of heat that the sample gained or lost, m is the mass of the sample, C is the specific heat and ΔT is the temperature change.

We already know some of these values.

Q = 874 J

m = 91 g

C = 0.90 J/g°C

ΔT = Tfinal - Tinitial

ΔT = Tfinal - 22 °C

Now we can replace these values in the previous formula and solve it for Tfinal to get the answer to our problem.

Q = m * C * ΔT

874 J = 91 g * 0.90 J/(g°C) * (Tfinal - 22 °C)

874 J/(91 g * 0.90 J/(g°C)) = (Tfinal - 22 °C)

Tfinal = 10.7 °C + 22 °C

Tfinal = 32.7 °C = 33 °C

Answer: The final temperature is 33 °C.