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Solve the following system equations.2x+3y=-15-7x-4y=-6x=y=

User Anisart
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Nestor, this is the solution to the problem:

Step 1: Let's isolate x in the first equation, this way:

2x + 3y = -15

2x = -15 - 3y

Dividing by 2 at both sides:

2x/2 = (-15 - 3y)/2

x = (-15 - 3y)/2

Step 2: Let's substitute x and solve for y in the second equation, as follows:

-7x - 4y = -6

-7 (-15 - 3y)/2 - 4y = -6

Solving parenthesis:

105 +21y/2 - 4y = -6

Multiplying by 2 at both sides:

105 + 21y - 8y = -12

Like terms:

13y = -12 - 105

13y = -117

y = -9

Step 3: Let's solve for x in the first equation, this way:

2x + 3y = -15

2x + 3 * -9 = -15

2x -27 = -15

Adding 27 at both sides:

2x - 27 + 27 = -15 + 27

2x = 12

Dividing by 2 at both sides:

2x/2 = 12/2

x = 6

User RonIT
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