Question

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Please answer the following essay question:
Suppose each dimension of a cube is increased. What happens to the surface area when each dimension is doubled, tripled or, quadrupled?

Answer 1

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Answer 2

Explanation:

Surface area of a cube = 6a²

When each dimension is doubled, Side =2a

Surface area = 6*(2a)² = 6 * 4*a² = 4*(6a²)

So, when each dimension is doubled, surface area is 4 times of the original surface.

a = 3a

Surface area = 6*(3a)² = 6 * 9 *a² = 9 *6a²

= 9 times the original area

a = 4a

Surface area = 6*(4a)² = 6* 16 * a²

= 16 * (6a²)

= 16 times of original area