Step-by-step explanation
to solve this we need to do a subtraction, so
remainign paper= total paper- cut paper so
Step 1
Let
![\begin{gathered} \text{total paper= 10 ft} \\ \text{cut paper= 2 }(3)/(4) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/7uhbqocwduw3fnk9q59p0l62n6pp8ew8th.png)
so
a) convert the mixed into improper fraction,
remember:
![a(b)/(c)=((a\cdot c)+b)/(c)](https://img.qammunity.org/2023/formulas/mathematics/college/5mgx8bgg4s6wm0ugtzsknrhu1p61itigo7.png)
so
![2\text{ }(3)/(4)=((2\cdot4)+3)/(4)=(11)/(4)](https://img.qammunity.org/2023/formulas/mathematics/high-school/utjnk9nptmxbyqph3swhvkeehcsye4zs32.png)
now, replace to solve
remainign paper= total paper- cut paper so
replace
![\begin{gathered} \text{remaining paper= 10-}(11)/(4) \\ \text{remaining paper= }(10\cdot4-1\cdot11)/(4)=(40-11)/(4)=(29)/(4) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/s8z1bmomujxc1tbnr8qqntn7rraiq6pgdd.png)
so, the remainin paper is
![(29)/(4)\text{ ft}](https://img.qammunity.org/2023/formulas/mathematics/high-school/n701ztf97kc22kl3mhmw3u3k1za01ss4h3.png)
I hope this helps you