Question

In the figure below, the segments JK and JL are tangent to the circle centered at O. Given that OK = 1.6 and

Answer 1

Triangles JOK and JOL are congruent because:

* They have one common side

* They both are right triangles

This means that sides JK and JL are congruent and JK = 3.

From the right triangle JOK we have the length of the two legs: 1.6 and 3, thus we can calculate the hypotenuse with the Pythagorean's theorem:

`\begin{gathered} OJ^2=3^3+1.6^2 \\ \text{Calculate:} \\ OJ^2=9+2.56=11.56 \\ OJ=\sqrt[]{11.56} \\ OJ=3.4 \end{gathered}`

OJ = 3.4