The two triangles are similar by side-angle-side
Here, we want to prove that triangle AEB is congruent to CEB
For both to be congruent, there must be some congruence rule that links both
Let us start with triangles FAB and BCD
Since two of the angles are equal, it is sure that the third angles are equal
Thus;
angle FAB = angle BCD
So, firstly, we have one of the angles of both triangles equal
Secondly, we already have it that AB = BC = 5
This means that we also have a side of each equal
Lastly, as we can see from the diagram, the side EB is common to both triangles, and this makes up for the third fact that the triangles are equal
So from all these, we have two equal sides and an equal angle
So, the congruence statement is SAS (side-angle-side)