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How much work is done by an applied force to lift a 15 Newton block 3.0 meters vertically at a constant speed?5 J4500 J4 J45 J

1 Answer

4 votes

The work done is 45 J.

Given data:

• The applied force is F=15 N.

,

• The distance traveled is d=3.0 m.

The work done can be calculated as,


\begin{gathered} W=Fd \\ W=(15)(3) \\ W=45\text{ J} \end{gathered}

Thus, the work done by the force is 45 J.

User Davidmytton
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