Question

this is a homework problem, I think you use sqrtx1-x2 + y1-y2 or something like that but im here because im not sure. thank you!

Answer 1

Answer:

v = 6i - 3j

Step-by-step explanation:

The initial point, P₁ = (-8, 6)

The terminal point, P₂ = (-2, 3)

v is the vector from the initial point P₁ to the terminal point P₂

`\begin{gathered} x=P_(2x)-P_(1x) \\ x=-2-(-8) \\ x=-2+8 \\ x=6 \end{gathered}`
`\begin{gathered} y=P_(2y)-P_(1y) \\ y=3-6 \\ y=-3 \end{gathered}`

The vector, v = xi + yj

v = 6i + (-3)j

v = 6i - 3j