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A loan of $1.070 was repaid at the end of 18 months with a check for $1.100 What annual rate of interest was charged?The annual rate of interest was charged at % (Round to two decimal places as needed)

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The formula for the simple interest is:


A=A_0\cdot(1+n\cdot r).

Where:

• A is the final amount of money after n years,

,

• A0 is the initial amount of money,

• r is the interest rate.

In this problem, we have.

• A = $1100,

,

• A0 = $1070,

,

• n = 1.5 years,

,

• r = ?.

Replacing the data of the problem in the equation above, we have:


\text{ \$1100 }=\text{ \$1070}(1+1.5\cdot r).

Solving the last equation for r, we get:


\begin{gathered} \frac{\text{ \$1100}}{\text{ \$1070}}=1+1.5r, \\ (1100)/(1070)-1=1.5r, \\ r=(1)/(1.5)\cdot((1100)/(1070)-1), \\ r\cong0.0187=1.87\%. \end{gathered}

Answer

The interest rate was charged at 1.87%.

User Ptkato
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