Question

Identify the center and radius of a circle whose equation is x2 + (y – 2)2 = 3

Answer 1

The center of the circle is (0, 2) and the radius is √3

The equation of a circle is;

`r^2=(x-h)^2+(y-k)^2`

In this case, we have:

`3=x^2+(y-2)^2`

Then:

`r^2=3\Rightarrow r=\sqrt[]{3}^{}`

r is the radius, then we know that already.

Now the center is (h, k) from the equation of a circle, above

In this case, the number that is resti