Solution:
Given:
![15-(-10)+(-8)-12+(-2)](https://img.qammunity.org/2023/formulas/mathematics/college/1dlxptnk8ekf8pmdjnxegdsghivs125bi2.png)
Since we have multiple operations, we solve using PEMDAS or BODMAS.
where;
![\begin{gathered} P=\text{Parentheses} \\ E=Exponents \\ M=\text{Multiplication} \\ D=\text{Division} \\ A=\text{Addition} \\ S=\text{Subtraction} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/2pjdy1n7wp30wzbzj8qklga8vtu58ac96r.png)
![\begin{gathered} B=\text{Bracket} \\ O=\text{Order} \\ D=\text{Division} \\ M=\text{Multiplication} \\ A=\text{Addition} \\ S=\text{Subtraction} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/5gumszhljznqq47lystw9swhq1ba36k92t.png)
From the above order, we solve the parentheses (or brackets first) using the directed number multiplication of signs.
Recall that;
![\begin{gathered} +*+=+ \\ -*-=+ \\ +*-=- \\ -*+=- \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/85l159r5z4llkqcv2fzusoilo5f58lkank.png)
Hence,
![\begin{gathered} 15-(-10)+(-8)-12+(-2) \\ =15+10-8-12-2 \\ =25-8-12-2 \\ =17-12-2 \\ =5-2 \\ =3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ax1tqqs7aolyvowk063n1pnapk1hbbyc2t.png)
Therefore,
![15-(-10)+(-8)-12+(-2)=3](https://img.qammunity.org/2023/formulas/mathematics/college/al0m6gcj8raskqkt01t0a9t523ibcw95hr.png)
The answer is 3.