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Plot four lines. Each lines should pass through the point on the y-axis

User Crusam
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we have that for each line, the y-intercept is the point (0,-2), then, we can use this point with another to find the slope, and then the equation of the line that passes through those points.

First, lets take the point (-4,3), then:


\begin{gathered} slope\colon \\ m=(3-(-2))/(-4-0)=(3+2)/(-4)=-(5)/(4) \\ equation\colon \\ y=-(5)/(4)x-2 \end{gathered}

for the point (1,-4), we have:


\begin{gathered} slope\colon \\ m=(-4-(-2))/(1-0)=(-4+2)/(1)=-2 \\ equation\colon \\ y=-2x-2 \end{gathered}

finally, for the point (-3,-5), we get:


\begin{gathered} slope\colon \\ m=(-5-(-2))/(-3-0)=(-5+2)/(-3)=(-3)/(-3)=1 \\ equation\colon \\ y=x-2 \end{gathered}

therefore, the missing lines are

y=x-2

y=-2x-2

y=-5/4x-2

User Shlomo
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