Answer:
v(1) = -36, v(2) = 0
Step-by-step explanation:
The given system of equations is:
-36 = v(1) +2v(2).........................(1)
36 = v(2) - v(1)...........................(2)
Add equation (1) and (2) together
-36 + 36 = 3v(2)
0 = 3v(2)
v(2) = 0/3
v(2) = 0
Substitute v(2) = 0 into equation (1)
-36 = v(1) + 2(0)
-36 = v(1) + 0
v(1) = -36
Therefore, the solutions to the system of equations are:
v(1) = -36, v(2) = 0