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Solve each equation by using the square root property. X^2–16x+64=8

2 Answers

3 votes

Answer:

Explanation:


(x-8)^(2)=-8

User Nicholas Summers
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7 votes

X^2–16x+64=8

Subtract 8 from both sides of the equation:

X^2–16x+64 -8=8-8

X^2–16x+56=0

Apply the quadratic formula:


\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Where:

a=1 . b=-16 , c = 56

Replacing:


\frac{16\pm\sqrt[]{(-16)^2-4(1*56)}}{2*1}
\frac{16\pm\sqrt[]{256-224}}{2}
\frac{16\pm\sqrt[]{32}}{2}

positive:


\frac{16+\sqrt[]{32}}{2}=\frac{16+4\sqrt[]{2}}{2}\text{ = }8+2\sqrt[]{2}

Negative:


\frac{16-\sqrt[]{32}}{2}\text{ =}\frac{16-4\sqrt[]{2}}{2}=8-2\sqrt[]{2}

User HTNW
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