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Consider these functions: f(x)= 1/3x^2 +4g(x)=9x-12 what is the value of g(f(x))

Consider these functions: f(x)= 1/3x^2 +4g(x)=9x-12 what is the value of g(f(x))-example-1
User Dcfg
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Answer

Step-by-step explanation

Given:


\begin{gathered} f(x)=(1)/(3)x^2+4 \\ g(x)=9x-12 \end{gathered}

To determine the value of g(f(x)), we substitute x with 1/3x^2+4 for g=9x-12:


\begin{gathered} g(x)=9x-12 \\ g((1)/(3)x^2+4)=9((1)/(3)x^2+4)-12 \\ Simplify \\ =3x^2+36-12 \\ =3x^2+24 \end{gathered}

Therefore, the value of g(f(x)) is C:


\begin{equation*} 3x^2+24 \end{equation*}

User Kalyanji
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