Question

Evaluate h(-8) for h(x)=1/4x² + 7x

Answer 1

h(-8) = -40

Step-by-step explanation:

Given the function:

`h(x)=(1)/(4)x^2+7x`

To evaluate the value of h(-8), we substitute -8 for x in h(x).

`\begin{gathered} h(-8)=(1)/(4)(-8)^2+7(-8) \\ =((1)/(4)*64)-56 \\ =16-56 \\ =-40 \end{gathered}`