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As shown in the diagram below, the angle of elevation from a point on the ground to the top of the tree is 34° If the point is 20 feet from the base of the tree, what is the height of the tree, to the nearest tenth of a foot

User RitchieD
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Angle elevation = 34°

Distance = 20 feets

Then

Height of tree= 20• Sin 34°

Sin 34°= 0.56

Then answer is

Height H= 20•0.56= 11.2 feets

User Witold Kowelski
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