We should first recognize that a dilation by a scale factor of 1/2 is actually a compression.
We are told the compression is done about the point (2,1):
What we should do is translate the whole figure so the origin is the point about which we do the compression. To do this, we subtract 2 from the x-coordinate of each vertex and we subtract 1 from the y-coordinate of each vertex.
With this in mind, to coordinates of the translation (TA, TB, TC) will be:
![TA^{^{}}=(-6-2,-3-1)=(-8,-4)](https://img.qammunity.org/2023/formulas/mathematics/college/mbeoalny5c0ab2tnj3ajpjs165u1xjfa4x.png)
![TB=(4-2,-1-1)=(2,-2)](https://img.qammunity.org/2023/formulas/mathematics/college/fjafu6l9w2cwh82h2474hzyh7vk6fhmzkq.png)
![TC=(2-2,7-1)=(0,6)](https://img.qammunity.org/2023/formulas/mathematics/college/ndd0sbibyv42s9ddg2u4yogwc29welfytp.png)
Now we multiply this new coordinates by the scale factor to obtain a new set of coordinates (A'', B'', C''):
![A^(\doubleprime)=(1)/(2)(-8,-4)=(-4,-2)](https://img.qammunity.org/2023/formulas/mathematics/college/ljv1189zgpevxpsvh2m80g10p9292lcr2p.png)
![B^(\doubleprime)=(1)/(2)(2,-2)=(1,-1)](https://img.qammunity.org/2023/formulas/mathematics/college/3i6v3p2ny8lxl98xaf342aa6kjqmzu6qhq.png)
![C^(\doubleprime)=(1)/(2)(1,6)=(0,3)](https://img.qammunity.org/2023/formulas/mathematics/college/jny4s81amoips9cd3fh717ji5nscl46dl2.png)
Finally, we translate the figure back were we started, so we add 2 to the x-coordinate and 1 to the y-coordinate to obtain A', B' and C':
![A^(\prime)=(-4+2,-2+1)=(-2,-1)](https://img.qammunity.org/2023/formulas/mathematics/college/4nblkgj3eu7v3wd09hipwc9xyl3m5yklhh.png)
![B^(\prime)=(1+2,-1+1)=(3,0)](https://img.qammunity.org/2023/formulas/mathematics/college/pw1ca1bbb5olxjt9x44jbduzaicpi5q4r7.png)
![C^(\prime)=(0+2,3+1)=(2,4)](https://img.qammunity.org/2023/formulas/mathematics/college/bs2whramewfbh23izt2k3x7frldh7mpasy.png)