The altitude and time of both Malik and Mila are provided in function form. The rate of climb can be gotten by evaluating the slope of the functions/graphs.
To calculate the slope, we use the formula:
![m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/78uaqhwt0aws3qfwxigaftpihnmb1gzxtp.png)
Mila's Ascension:
We have the following parameters from the table:
![\begin{gathered} (x_1,y_1)=(1,721) \\ (x_2,y_2)=(2,1442) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/pyvay82jzp2x6adqn0dpv7ypb6rzfeicjj.png)
Hence, we can calculate the rate of climb to be:
![\begin{gathered} m_1=(1442-721)/(2-1) \\ m_1=721 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/jqs9zigni687acigtamejhct19bvtxmr2c.png)
Therefore, Mila ascends at 721 ft/h.
Malik's Ascension:
We have the following parameters from the graph:
![\begin{gathered} (x_1,y_1)=(1,693) \\ (x_2,y_2)=(2,1386) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/mki2y7j8izcwxwu9f7nv7vie8vnteu0lvy.png)
Hence, we can calculate the rate of climb to be:
![\begin{gathered} m_2=(1386-693)/(2-1) \\ m_2=693 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/v2qctpmhj9trysyky582cqm38vpis1wapg.png)
Therefore, Malik ascends at 693 ft/h.
The difference between both ascension rates is how much faster one is going than the other. This is given to be:
![D=m_2-m_1=721-693=28](https://img.qammunity.org/2023/formulas/mathematics/college/t301nxrqal9fvpjckwp7pwlehosf5fx6z3.png)
ANSWERS:
1) Mila is climbing at a faster rate.
2) Mila is climbing faster than Malik at a rate of 28 ft/h.