1 Answer

Cuiboy · Answer 1 · 2023-08-25T22:37:55+0000

Solution:

Consider the following diagram of the rectangular park given in the problem:

now, the perimeter P of this figure is the sum of all its sides, that is:

$P\text{ = 2L + 2W}$

But, the length of the park is 10,729.1 inches longer than the width, that is:

EQUATION 1:

$L\text{ = 10729.1+W}$

Substituting the above expression into the perimeter equation, we get:

$P\text{ = 2 (10729.1 + W) + 2W}$

this is equivalent to:

$P\text{ = 2 (10729.1) + 2W + 2W}$

this is equivalent to:

$P\text{ = 21458.2 +4W}$

But P = 23083.1 inches, then replacing this data into the previous equation, e get:

$23083.1\text{= 21458.2 +4W}$

solving for 4W, we get:

$\text{ 4W = }23083.1-\text{21458.2}=\text{ 1624.9}$

solving for W, we get:

$\text{ W = }\frac{\text{1624.9}}{4}=406.2$

now, replacing the above result into equation 1, we get:

$L\text{ = 10729.1+W = 10729.1+}406.2\text{ = 11135.3}$

so that, we can conclude that the correct answer is:

$L\text{ = 11135.3}$

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