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Assume the perimeter of a particular sector is 40 cma) Express the measurement of the angle of the sector as a function of the radius of the sector b) express the area of the sector as a function of the radiu

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We are asked to determine an equation for the angle of a sector as a function of its radius. To do that let's remember that we have the following relationship:


s=r\theta

Where "s" is the measurement of the arc of the sector and "r" its radius. Solving for the angle we get:


\theta=(s)/(r)

Since we are given the perimeter, we can use the formula for the perimeter of a circular sector:


P=2r+s

Solving for "s":


P-2r=s

Replacing the value of the perimeter:


40-2r=s

Replacing the value of "s" in the formula for the angle:


\theta=(40-2r)/(r)

This is the formula for the angle of the sector as a function of the radius.

To find the formula for the area, let's remember that the area of a circular sector is given by the following equation:


A=(1)/(2)r^2\theta

Replacing the value of the angle we get:


A=(1)/(2)r^2((40-2r)/(r))

Simplifying:


A=r(20-r)

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