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Solve the equation. d2 + 5 = 41 р and d= 1

Solve the equation. d2 + 5 = 41 р and d= 1-example-1
User Husky
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1 Answer

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ANSWERS

• d = 6

,

• d = -6

Step-by-step explanation

To solve this equation first we have to substract 5 from both sides of the equation:


\begin{gathered} d^2+5-5=41-5 \\ d^2=36 \end{gathered}

Now we have to apply the square root on both sides of the equation. Remember that the square root has 2 results: one positive and one negative. But if you apply the square root to a square power, you have the absolute value:


\begin{gathered} \sqrt[]{d^2}=\pm\sqrt[]{36} \\ d=\pm6 \end{gathered}

Therefore the solutions of this equation are d = 6 and d = -6

User Brian Duncan
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