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What is the solution set to this equation?108, (2 - 3) + 108, (7 + 3) = 2

What is the solution set to this equation?108, (2 - 3) + 108, (7 + 3) = 2-example-1
User Latroy
by
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1 Answer

2 votes

Solution

We will solve the question using the laws of logarithm

Some of the laws we will use are stated below


\log_xa+\log_xb=\log_x(a* b)

Also ,


\begin{gathered} \log_xy=z \\ \\ x^z=y \end{gathered}

Given ;


\log_4(x-3)+\log_4(x+3)=2

Using same logarithm base ruke , we have


\log_4(x-3)(x+3)=2

Removing the logarithm , we have


4^2=(x-3)(x+3)

We can now solve the equation obtained as shown below


\begin{gathered} 16=x^2+3x-3x-9 \\ 16=x^2-9 \\ x^2=16+9 \\ x^2=25 \\ x=\pm√(25) \\ x=\pm5 \end{gathered}

We will ignore x is negative 5 , since we cannot have a negative logarithm

The final answer is x=5

OPTION B

User Andrea Di Giorgi
by
8.2k points

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