Answer
Minimumscore required for therecruitment
Step-by-step explanation
For a normal distribution, it is quite important to explain what it means to normalize the required score.
The standardized score for any value is the value minus the mean then divided by the standard deviation.
z = (x - μ)/σ
z = standardized score of the minimum score required to be in the 90th percentile
x = minimum required score to be in the 90th percentile
μ = mean of the distribution = 404
σ = standard deviation of the distribution = 84
The minimum score required to be in the 90th percentile will be the score that is greater than 90% of all the scores.
P(Z ≤ z) = 0.90
From the tables,
z = 1.282
z = (x - μ)/σ
z = 1.282
x = ?
μ = mean of the distribution = 404
σ = standard deviation of the distribution = 84
1.282 = (x - 404)/84
x - 404 = (84) (1.282)
x - 404 = 107.688
x = 404 + 107.688
x = 511.688 = 511.7
Hope this Helps!!!