Given that two balls undergo elastic collision.
The mass of the first ball is m1 = 5 kg
The mass of the second ball is m2 = 6 kg.
Let us take the ball moving towards the left as positive and the ball moving towards the right as negative.
The velocity of the first ball before the collision is
![v_o1=-2\text{ m/s}](https://img.qammunity.org/2023/formulas/physics/college/1dlkcakz13cx7kb2dskym2x8jvj3r3q85i.png)
The negative sign indicates that it moves towards the right.
The velocity of the second ball before the collision is
![v_o2=2\text{ m/s}](https://img.qammunity.org/2023/formulas/physics/college/ew9xgtwmkvcurxtblmm0e4bpcjk1cj7qlh.png)
The positive sign indicates that it moves towards the left.
The velocity of the first ball after the collision is
![v_f1=3\text{ m/s}](https://img.qammunity.org/2023/formulas/physics/college/vtnwf1hdpf7dsn2zkd2i7d0p97xnrh3j07.png)
The positive sign indicates that it moves towards the left.
We have to find the velocity of the second ball after the collision.
According to the conservation of momentum,
![m1v_o1+m2v_o2=m1v_f1+m2v_f2](https://img.qammunity.org/2023/formulas/physics/college/dl024wjyhegwcnd0u545i7oi1j43bkpy1a.png)
Substituting the values, the velocity of the second ball will be
![\begin{gathered} 5*(-2)+6*12=5*3+6* v_f2 \\ v_f2=(-10+12-15)/(6) \\ =-(13)/(6) \\ =-2.16\text{ m/s} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/6yfpx7bmk4eh9c4j5lacl5uvxn6bto6d2b.png)
Here, the negative sign indicates that the ball is moving towards the right.
Thus, the correct option is 2.16 m/s to the right.