Question

Can someone please help me with questions 13 and 14?

Answer 1

Answer: #13 is 26, #14 is 18

Explanation:

13.

The whole line has length
`8x - 20`, and
`AB = BC = 3x - 1`. Thus

`(3x -1) + (3x-1)=8x-20\\6x - 2 = 8x - 20\\18 = 2x\\x = 9`

Now we plug this into
`3x - 1` (since this is the length of BC) to get

`3(9) - 1 = \boxed{26}`.

14.

We can use the fact that CG = GD, so
`5x - 1 = 7x - 13` and thus
`x = 6`.

We know
`EG = EF - GF`, so

`EG = (6x - 4) - 13 = (6 \cdot 6 - 4) - 14 = \boxed{18}.`