We are to solve the inequality:
|x + 3| + 2 ≤ 4
First let's subtract 2 from both sides
|x + 3| + 2 - 2 ≤ 4 - 2
|x + 3| ≤ 2
Apply absolute rule: if |u| ≤ a, a > 0 then -a ≤ u ≤ a
-2 ≤ x + 3 ≤ 2
x + 3 ≥ -2 and x + 3 ≤ 2
x ≥ -5 and x ≤ -1
-5 ≤ x ≤ -1
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