GIVEN:
We are given the following quadratic function;
Required;
To determine which viewing window would be suitable to see all of the intercepts and the minimum as closely as possible.
Step-by-step solution;
There are two ways to solve this, either by graphing, or by algebraic method. Graphing the function is pretty much easier and faster to dtermine the window dimensions that would allow us see all the intercepts and minimum.
We shall now graph the equation and use the values on the axis;
We can see from the graph uploaded above that the minimum is at
With the minimum value so close to y = -80, we can say the dimensions for the y-axis from -80 to 80.
Also, the intercepts are at the points;
This shows that the intercept on the left is closer to -20 while the other one is just close to zero (the origin). That means the dimensions for the x-axis would be from -20 to 5.
Therefore, the correct answer is
ANSWER:
The x-axis is from -20 to 5, the y-axis is from -80 to 80.
The first option is the correct answer