Question

What is the length of the hypotenuse of right ∆UVW shown?A. 99 B. 4√105 C.41 D. 42

Answer 1

You use the pythagoras theorem to find the lenght of the hypotenuse:

`\begin{gathered} h^2=l^2+l^2 \\ h=\sqrt[]{l^2+l^2} \end{gathered}`

You have the measure of the two legs: 40 and 9:

`\begin{gathered} h=\sqrt[]{40^2+9^2} \\ h=\sqrt[]{1600+81} \\ h=\sqrt[]{1681} \\ h=41 \end{gathered}`The hypotenuse is 41 units.