Question

Find the 79th term of the following arithmetic sequence.2, 11, 20, 29,

Answer 1

The arithmetic sequence formula is:

`a_n=a_1+(n-1)d`

where an is the nth term, a1 is the first term, and d is the common difference.

In the sequence,

2, 11, 20, 29,

a1 = 2, and the common difference is:

d = 11 - 2 = 20 - 11 = 29 - 20 = 9

Then,

`\begin{gathered} a_(79)=2+(79-1)9 \\ a_(79)=2+(78)9 \\ a_(79)=2+702 \\ a_(79)=704 \end{gathered}`

the 79th term is 704