Question

Formulas neededa) Equation of a line in slope-yintercept form y = f(x) = mx + bb) Equation of a line slope-pointy - y = m (x - x)(10 points)9) The slope of the tangent to a function f(x) at point(2,7) is m, = -3. Write the equation of the tangent lineat the given point.

Answer 1

Let:

`\begin{gathered} (x1,y1)=(2,7) \\ m=-3 \end{gathered}`

Using the point-slope equation:

`\begin{gathered} y-y1=m(x-x1) \\ y-7=-3(x-2) \\ y-7=-3x+6 \\ y=-3x+13 \end{gathered}`

Answer:

y = -3x + 13