Question

Q2 What is the equation of the circle graphed below? o (x - 5)2 + y2 = 3 O x² + (x + 5)2 = 3 6 O (x + 5)2 + y2 = 9 0x² + (x - 5)2 = 9 А B -4 -2 0 2. 6 search O a

Answer 1

The general equation of a circle is:

`(x-h)^2+(y-k)^2=r^2`

where (h, k) is the center and r the radius of the circle.

From the graph, the center is located at (0, 5), that is, h = 0 and k = 5. And the radius is 3, that is, r = 3. Substituting these values into the general equation, we get:

`\begin{gathered} (x-0)^2+(y-5)^2=3^2 \\ x^2+(y-5)^2=9 \end{gathered}`