1 Answer

Lucas Lopes · Answer 1 · 2023-05-24T19:53:17+0000

The perimeter of a circumference is 2πr, where r is the radius of the circumference. Thus, the perimeter of half a circumference is πr.

The semi-circumference part of the figure has a diameter of 5 ft. So, its radius, which is half the diameter, is 2.5 ft.

So, the length, in feet, of that part is

2.5π ≅ 2.5 * 3.14 ≅ 7.85

The length, in feet, of the bottom plus the top of the rectangular part is 8 + 8 = 16.

The bottom of the triangle measures, in feet, 3.

And the hypotenuse of the triangle (the left side of the figure), measures, in feet:

$√(3² +5²)=\sqrt[]{9+25}=\sqrt[]{34}\cong5.83$

Then, adding all those parts, we find the perimeter, in feet, to be:

$7.85+16+3+5.83=32.68\cong32.7$

Therefore, the perimeter of the figure, rounded to one decimal place, is:

32.7 ft

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