Question

The question is in the image. Answer the question 6.

Answer 1

Question 6.

Using the pythagorean theorem to find the value of r:

`r=√(x^2+y^2)=√(3^2+1^2)=√(9+1)=√(10)`

Next, using:

x = 3

y = 1

The six trigonometric functions are given by:

`\begin{gathered} \sin\theta=(y)/(r)=(1)/(√(10)) \\ \tan\theta=(y)/(x)=(1)/(3) \\ sec\theta=(r)/(x)=(√(10))/(3) \\ \cos\theta=(x)/(r)=(3)/(√(10)) \\ csc\theta=(r)/(y)=(√(10))/(1) \\ cot\theta=(x)/(y)=(3)/(1)=3 \end{gathered}`