Question

Hello! I need some assistance with this homework question for precalculus, please?HW Q28

Answer 1

`3^(log_36)`

To evaluate the given expression, simply convert the expression to logarithmic form.

`\begin{gathered} y=3^(log_36) \\ Convert. \\ \begin{equation*} log_36=log_3y \end{equation*} \end{gathered}`

Based on the conversion, we can see that the value of y is 6. Hence, the value of 3 raised to the power of log 6 base 3 is 6.

`3^(log_36)=6`

The answer is 6.