Question

addison is sliding across the floor in his socks. If Mr. Mangan has amass of 86 kg and the floor applies 150 N of friction force onto Mr.Mangan, what is the coefficient of kinetic friction between Mr.Mangan's socks and the floor?

Answer 1

Given data:

* The mass of Mr. Mangan is 86 kg.

* The friction force acting on the Mr. Mangan is 150 N.

Solution:

The normal force acting on the Mr. Mangan is,

`F_N=mg`

where m is the mass of Mr. Mangan, and g is the acceleration due to gravity,

Substituting the known values,

`\begin{gathered} F_N=86*9.8 \\ F_N=842.8\text{ N} \end{gathered}`

The frictional force acting on the Mr. Mangan in terms of coefficient of friciton is,

`F_{\text{k}}=\mu_kF_N`
`\text{where }\mu_k\text{ is the coefficient of friction,}`

Substituting the known values,

`\begin{gathered} 150=\mu_k*842.8 \\ \mu_k=(150)/(842.8) \\ \mu_k=0.18 \end{gathered}`

Thus, the coefficient of kinetic friction is 0.18.