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What is the inverse of f(x) = 1/3x +2?oh(x) =- *x+2O h(x) =-X-2O h(x) = 3x - 2O h(x) = 3x - 6

User Voivoid
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Having the function f(x):


f(x)=(1)/(3)x+2

You can find its inverse as follows:

Rewrite it with:


f(x)=y
y=(1)/(3)x+2

Solve for the variable "x":


\begin{gathered} y-2=(1)/(3)x \\ 3(y-2)=x \\ x=3y-6 \end{gathered}

Now you have to exchange the variables:


y=3x-6

Finally, rewrite h(x)=y:


h(x)=3x-6

The answer is the LAST OPTION.

User Piotr Tempes
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