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Select the correct answer.A survey was given to randomly selected employees who drive to work. Each employee was asked to report if they had received a speeding ticket on their morning commute to work any time in the last year. The results are in the table.Which conclusion can be made from the data?A. The probability of an employee receiving a speeding ticket given that they regularly leave for work late is the same as the probability of an employee not receiving a speeding ticket given that they regularly leave for work early or on time.B. The probability of an employee receiving a speeding ticket given that they regularly leave for work early or on time is less than the probability of an employee not receiving a speeding ticket given that they regularly leave for work late.C. Regularly leaving for work late and receiving a speeding ticket are independent events.D. Employees who regularly leave for work late are less likely to receive a speeding ticket than employees who regularly leave for work early or on time.

Select the correct answer.A survey was given to randomly selected employees who drive-example-1
User Duggu
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2 Answers

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Answer: The probability of an employee receiving a speeding ticket given that they regularly leave for work early or on time is less than the probability of an employee not receiving a speeding ticket given that they regularly leave for work late.

Step-by-step explanation: Correct on Edmentum

Select the correct answer.A survey was given to randomly selected employees who drive-example-1
User Kmoser
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3 votes
Answer:

Option B is the conclusion that can be made from the given table

The probability of an employee receiving a speeding ticket given that they regularly leave for work early or on time is less than the probability of an employee not receiving a speeding ticket given that they regularly leave for work late.

Step-by-step explanation:

We need to test the options to know which one of them is correct

A.

The probability of an employee receiving a speeding ticket given that they regularly leave for work late is the same as the probability of an employee not receiving a speeding ticket given that they regularly leave for work early or on time.


\begin{gathered} (56)/(65)=(81)/(86) \\ \\ NOT\text{ TRUE} \end{gathered}

B.

The probability of an employee receiving a speeding ticket given that they regularly leave for work early or on time is less than the probability of an employee not receiving a speeding ticket given that they regularly leave for work late.


\begin{gathered} (5)/(86)<(9)/(65) \\ \\ TRUE \end{gathered}

C.

Regularly leaving for work late and receiving a speeding ticket are independent events.

NOT TRUE

D.

Employees who regularly leave for work late are less likely to receive a speeding ticket than employees who regularly leave for work early or on time.

P(Speeding ticket given they leave work late) = 56/65 = 0.8615

P(Speeding ticket given they leave work early or on time) = 5/86 = 0.0581

NOT TRUE

User Kristal
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