Answer:
A) T = 13/62N +(50 45/62)
B) T ≈ 83.9 °F
Explanation:
A)
The equation can be written in slope-intercept form by finding the slope (m) and the y-intercept (b). The formulas are ...
m = (y2 -y1)/(x2 -x1)
b = y1 -m(x1)
For the given points (111, 74) and (173, 87), the slope is ...
m = (87 -74)/(173 -111) = 13/62
The y-intercept is ...
b = 74 -(13/62)(111) = 50 45/62
Then the equation in slope-intercept form is ...
y = mx +b
T = 13/62N +(50 45/62)
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B)
For a chirp rate of N=158, the temperature is approximately ...
T = (13/62)(158) +(50 45/62) = 33 8/62 +50 45/62 = 83 53/62
T ≈ 83.9 °F