Question

Dallas, Texas has an elevation of 200 feet above sea level. The city of Jacksonville is 300 feet less than the elevation of Dallas. Select all options that apply to Jacksonville. at sea level below sea level above sea level elevation of -100 feet elevation of 100 feet

Answer 1

below sea level;

-100 feets

Explanation:

Given that:

Dallas, Texas elevation = 200 feets

Jacksonville = 300 feets less than elevation of Dallas

Hence, elevation of Jacksonville :

Dallas elevation - 300 feets

200 feets - 300 feets = - 100 feets

Hence Elevation of Jacksonville city is - 100 feets

-100 feets, means elevation of Jacksonville city is below sea level (elevation points less than 0, are below sea level).