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User Cammace
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Hello there. To solve this question, we'll have to remember some properties about slopes of a terminal ray.

Given that the initial ray of an angle it pointing in 12 o'clock direction and turns counterclockwise, when θ is the measure of the varying angle in radians, we have to determine:

The slope of the terminal ray, if θ = 0.8

Write an expression (in terms of θ) that represents the varying slope of the terminal ray.

We start drawing the diagram. With a circle with radius R, we make:

The slope of the terminal ray can be determined by taking the tangent of the angle, but don't forget this angle starts after 90º.

Therefore the slope might be:


m=\tan(90^(\circ)+\theta)=-\cot(\theta)

This is also the expression for the varying slope of the terminal ray, in terms of θ.

To find the slope when θ = 0.8, simply plug it, in radians, and use a calculator to evaluate the expression:


m=-\cot(0.8)\approx0.97121

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User Hrabosch
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