Question

Help and be precise on the answers on the page

Answer 1

As per given by the question,

There are given that the equation,

`x^3+x^{2^{}}-16x-16;x+1`

Now,

From the given equation,

`x^3+x^{2^{}}-16x-16;x+1`

According to there are already given that original polynomial, x+1;

That means,

There is one point is already given for satisfied the quadratic equation.

Now,

For the two another factor;

If take the (x+1) factor from the given equation,

Then,

The equation becomes;

`\begin{gathered} x^2-4x+4x-16=0 \\ x^2-16=0^{} \end{gathered}`

So,

The equation and factor is,

`\begin{gathered} x^2+0x+(-16) \\ (x+4)(x-4) \end{gathered}`

Then the final factor of tyhe given quadratic equation is,

`(x+1)(x+4)(x-4)`

Hence, the equation and their factor and final factor is;

`\begin{gathered} x^2+0x+(-16)^{}_{} \\ =(x+4)(x-4) \end{gathered}`

And, the final factor is;

`(x+1)(x+4)(x-4)`