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Help and be precise on the answers on the page

Help and be precise on the answers on the page-example-1
User MrMuppet
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As per given by the question,

There are given that the equation,


x^3+x^{2^{}}-16x-16;x+1

Now,

From the given equation,


x^3+x^{2^{}}-16x-16;x+1

According to there are already given that original polynomial, x+1;

That means,

There is one point is already given for satisfied the quadratic equation.

Now,

For the two another factor;

If take the (x+1) factor from the given equation,

Then,

The equation becomes;


\begin{gathered} x^2-4x+4x-16=0 \\ x^2-16=0^{} \end{gathered}

So,

The equation and factor is,


\begin{gathered} x^2+0x+(-16) \\ (x+4)(x-4) \end{gathered}

Then the final factor of tyhe given quadratic equation is,


(x+1)(x+4)(x-4)

Hence, the equation and their factor and final factor is;


\begin{gathered} x^2+0x+(-16)^{}_{} \\ =(x+4)(x-4) \end{gathered}

And, the final factor is;


(x+1)(x+4)(x-4)

User Xsznix
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