Question

Ammonia is produced by the reaction of hydrogen and nitrogen as follows:N2(g)+3H2(g)→2NH3(g)ammoniaHow many moles of N2 reacted if 0.40 mol of NH3 is produced? Express the number of moles to two significant figures

Answer 1

They give us the balanced equation of the reaction for the production of ammonia. We see that for every mole of N2 that reacts, two moles of ammonia are formed. This corresponds to the ratio, that is, the ratio N2 to NH3 is 1/2. therefore, if 0.40 mol of MH3 is obtained, the moles of N2 that reacted were:

`molN_2=givenmolNH_3*(1molN_2)/(2molNH_3)`
`\begin{gathered} molN_2=0.40molNH_3*(1molN_2)/(2molNH_3) \\ molN_2=0.20molN_2 \end{gathered}`

Answer: It reacted 0.20 mol of N2