Question

A race car traveling northward on a straight, level track at a constant speed travels 0.739 km in 18.0 s. The return trip over the same track is made in 23.0 s.(a)What is the average velocity of the car in m/s for the first leg of the run? m/s(b)What is the average velocity (in m/s) for the total trip? m/s

Answer 1

Answer:

a) The average velocity of the car for the first leg of the run = 41.06 m/s

b) The average velocity for the total trip = 0 m/s

Step-by-step explanation:

a) In the first leg of the journey:

Displacement covered = 0.739 km = 0.739 x 1000m = 739 m

The time taken = 18.0 s

The average velocity of the car = Displacement/Time

The average velocity of the car = 739/18

The average velocity of the car = 41.06 m/s

b) For the total trip

The displacement of the first leg = 0.739 km due North

The displacement of the return trip = 0.739 km (through the same trace)

Total displacement = 0.739 km - 0.739 km

Total displacement = 0 km = 0 m

Average velocity for the total trip = Displacemt/time

Average velocity for the total trip = 0 /time = 0 m/s