Graphing the points given and the corresponding sides, we have:
We can see that the distance between P and Q and the distance between R and S is 7 units (they have the same y-coordinate, so the distance is the difference in x-coordinates).
Also, the vertical distance between Q and R and the vertical distance between P and S is 9 units (just the difference in y-coordinates).
Since this figure is a parallelogram (opposite sides are parallel), we can calculate the area as the base PQ times the height (the height is 9 units):
![\text{Area}=7\cdot9=63](https://img.qammunity.org/2023/formulas/mathematics/college/95tlxuq2mzvrhlytdcu24hi2ykleotlg6q.png)
The length of segments QR and PS can be calculated using Pythagorean Theorem, with the difference in x-coordinates being 3 units and the difference in y-coordinates being 9 units:
![\begin{gathered} QR^2=3^2+9^2 \\ QR^2=9+81 \\ QR^2=90 \\ QR=9.49 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/mp26di0gxbgb3q3isr14s2ox0dv8bdymn1.png)
So the perimeter of this parallelogram is:
![\text{Perimeter}=7+9.49+7+9.49=32.98](https://img.qammunity.org/2023/formulas/mathematics/college/55k34pfysbvkm7hq6z6yqfo2glutoympzp.png)