-|14-6(1)+7(-6+2(-2)|

Question

asked Dec 12, 2023 120k views

1 Answer

Gaumann · Answer 1 · 2023-12-16T12:08:09+0000

The given expression is

$-\lvert14-6n+7(q+2t)\rvert$

n = 1, q = -6, and t = -2

$-\lvert14-6(1)+7\lbrack(-6)+2(-2)\rbrack\rvert=$

Simplify the square bracket

$\begin{gathered} -\lvert14-6+7\lbrack-6+(-4)\rbrack\rvert= \\ -\lvert14-6+7\lbrack-10\rbrack\rvert= \end{gathered}$

Multiply 7 by -10

$\begin{gathered} -\lvert14-6+(-70)\rvert= \\ -\lvert14-6-70\rvert= \end{gathered}$

Add all terms

$-\lvert14-6-70\rvert=-\lvert-62\rvert$

The absolute value will cancel the negative of 62 (I-62I = 62)

$-\lvert-62\rvert=-62$

The answer is -62