Question

When 47.3 J of heat is added to 13.0 g of a liquid, its temperature rises by 1.73 ∘C.What is the heat capacity of the liquid?

Answer 1

In order to determine the heat capacity of the liquid, use the following formula for the heat gained by the liquid:

`Q=mc\Delta T`

where

m: mass = 13.0 g

c = ?

ΔT: change in temperature = 1.73 ∘C

Q: heat gained by the liquid = 47.3 J

solve the equation for c and replace the previous values:

`c=(Q)/(m\cdot\Delta T)=(47.3J)/(13.0g\cdot1.73C)=2.10\text{ J/g}\circ\text{C}`

Hence, the heat capacity of the liquid is 2.10 J/g∘C